03-13-2008, 06:04 AM
[SIZE="6"]My hopes are that some kind soul will take a moment to explain how log is used in this problem:[/SIZE]
1.333 = (1+I)[SIZE="1"]n[/SIZE]
log 1.3333 = 4 log (1+I)
0.1248 = 4 log (1+I)
.0312 = log (1+I)
1.075 = 1+I
By what means does 'log 1.333' equal 0.1248?:o
Thank you, in advance, for your help
1.333 = (1+I)[SIZE="1"]n[/SIZE]
log 1.3333 = 4 log (1+I)
0.1248 = 4 log (1+I)
.0312 = log (1+I)
1.075 = 1+I
By what means does 'log 1.333' equal 0.1248?:o
Thank you, in advance, for your help
It's not that I'm so smart, it's just that I stay with problems longer. ~Albert Einstein
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