06-20-2019, 10:04 PM
Does anyone know how to solve this problem? (attached)
Math Help
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(06-20-2019, 10:04 PM)Giantzebra Wrote: Does anyone know how to solve this problem? (attached) The answer is "e", infinity. As x approaches 2, f(x) approaches -1. That causes the denominator to approach 0, which causes the function as a whole to approach infinity.
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06-21-2019, 08:44 AM
So because the denominator approaches zero the function approaches infinity?
06-21-2019, 08:52 AM
(06-21-2019, 08:44 AM)Giantzebra Wrote: So because the denominator approaches zero the function approaches infinity? Yes. As the denominator gets smaller, the function as a whole keeps getting larger. 1/1 = 1 1/0.01=100 1/0.00000000001 = 100000000000 It really doesn't matter what the numerator is so long as it's a real number.
NanoDegree: Intro to Self-Driving Cars (2019)
Coursera: Stanford Machine Learning (2019) TESU: BA in Comp Sci (2016) TECEP:Env Ethics (2015); TESU PLA:Software Eng, Computer Arch, C++, Advanced C++, Data Struct (2015); TESU Courses:Capstone, Database Mngmnt Sys, Op Sys, Artificial Intel, Discrete Math, Intro to Portfolio Dev, Intro PLA (2014-16); DSST:Anthro, Pers Fin, Astronomy (2014); CLEP:Intro to Soc (2014); Saylor.org:Intro to Computers (2014); CC: 69 units (1980-88) PLA Tips Thread - TESU: What is in a Portfolio?
06-22-2019, 11:28 PM
(06-21-2019, 08:52 AM)davewill Wrote:Does this mean that the answer would be infinity for any sine function?(06-21-2019, 08:44 AM)Giantzebra Wrote: So because the denominator approaches zero the function approaches infinity?
06-23-2019, 12:58 AM
(This post was last modified: 06-23-2019, 01:06 AM by MrBossmanJr.)
(06-22-2019, 11:28 PM)Giantzebra Wrote:(06-21-2019, 08:52 AM)davewill Wrote:Does this mean that the answer would be infinity for any sine function?(06-21-2019, 08:44 AM)Giantzebra Wrote: So because the denominator approaches zero the function approaches infinity? Oh man, I haven't done this in awhile. The graph shows that the limit as x approaches 2 should be -1, but it states that x / ( f(x) + 1) ). So, it would end up being 2 / ( -1 + 1 ) which is 2/0. 2 cannot be divided by 0 because it is not possible. Therefore, shouldn't the limit be undefined. EDIT: Oh wait nevermind. You are suppose to fill in numbers close to that value to see where it would end up, hence being infinity. I'm confused by the question "Does this mean that the answer would be infinity for any sine function?", but I think it would depend on what x is approaching for that particular expression.
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06-23-2019, 06:53 PM
(06-22-2019, 11:28 PM)Giantzebra Wrote: Does this mean that the answer would be infinity for any sine function? No. You have analyze the particular function and limit to figure out the answer. A different function or different limit would have different answer.
NanoDegree: Intro to Self-Driving Cars (2019)
Coursera: Stanford Machine Learning (2019) TESU: BA in Comp Sci (2016) TECEP:Env Ethics (2015); TESU PLA:Software Eng, Computer Arch, C++, Advanced C++, Data Struct (2015); TESU Courses:Capstone, Database Mngmnt Sys, Op Sys, Artificial Intel, Discrete Math, Intro to Portfolio Dev, Intro PLA (2014-16); DSST:Anthro, Pers Fin, Astronomy (2014); CLEP:Intro to Soc (2014); Saylor.org:Intro to Computers (2014); CC: 69 units (1980-88) PLA Tips Thread - TESU: What is in a Portfolio?
06-25-2019, 05:17 PM
All I see in the document is a function. What is the question asking you to do?
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06-25-2019, 05:18 PM
I'm guessing you are trying to find the derivative.
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Boston University: MS in Software Development Thomas Edison State University: BA in Liberal Studies |
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